G=SH
一个积分的解法

线性方程解法

痴心男http://im.cx/n posted @ 2008年11月21日 00:58 in 未分类 , 1012 阅读

$$\[ \left[ {\begin{array}{*{20}c}    1 & 1 & 1  \\    3 & 1 & { - 1}  \\    5 & { - 2} & 3  \\ \end{array}} \right]\left[ {\begin{array}{*{20}c}    x  \\    y  \\    z  \\ \end{array}} \right] = \left[ {\begin{array}{*{20}c}    6  \\    2  \\    {10}  \\ \end{array}} \right] \] $$

设最左边的矩阵等于A,等式两边都乘以A的逆矩阵。那么:

\[ \left[ {\begin{array}{*{20}c}    x  \\    y  \\    z  \\ \end{array}} \right] = \left[ {\begin{array}{*{20}c}    1 & 1 & 1  \\    3 & 1 & { - 1}  \\    5 & { - 2} & 3  \\ \end{array}} \right]^{ - 1} \left[ {\begin{array}{*{20}c}    6  \\    2  \\    {10}  \\ \end{array}} \right] \]

\[ \left[ {\begin{array}{*{20}c}    x  \\    y  \\    z  \\ \end{array}} \right] = \left[ {\begin{array}{*{20}c}    { - 0.0417} & {0.2083} & {0.0833}  \\    {0.5833} & {0.0833} & { - 0.1667}  \\    {0.4583} & { - 0.2917} & {0.0833}  \\ \end{array}} \right]\left[ {\begin{array}{*{20}c}    6  \\    2  \\    {10}  \\ \end{array}} \right] \]

\[ \left[ {\begin{array}{*{20}c}    x  \\    y  \\    z  \\ \end{array}} \right] = \left[ {\begin{array}{*{20}c}    1  \\    2  \\    3  \\ \end{array}} \right] \]

 

  • 无匹配

登录 *


loading captcha image...
(输入验证码)
or Ctrl+Enter